Συνδεδεμένοι δεκαεξαδικό σε κείμενο αποκωδικοποιητή

I am trying to use str.encode() but I get

>>> "hello".encode(hex)Traceback (most recent call last):  File "<stdin>", line 1, in <module>TypeError: must be string, not builtin_function_or_method

I have tried a bunch of variations and they seem to all work in Python 2.5.2, so what do I need to do to get them to work in Python 3.1?

I want to take an integer (that will be <= 255), to a hex string representation

e.g.: I want to pass in 65 and get out '\x41', or 255 and get '\xff'.

I've tried doing this with the struct.pack('c',65), but that chokes on anything above 9 since it wants to take in a single character string.

I'm trying to convert a String of hex to ASCII, using this:

public void ConvertHex(String hexString){    StringBuilder sb = new StringBuilder();    for (int i = 0; i < hexString.Length; i += 2)    {        String hs = hexString.Substring(i, i + 2);        System.Convert.ToChar(System.Convert.ToUInt32(hexString.Substring(0, 2), 16)).ToString();    }    String ascii = sb.ToString();    MessageBox.Show(ascii);}

but I get an out or bounds exception, I'm sure its a glaring error but other code I have tried does not work either. What am I doing wrong?

I have a function that takes in a value for an address in memory as a string (user input). It is input is taken in as a hex value

char * address = new char[16];address = "fff85044";

How would I convert that string into a readable address value?A sort of stoh (string to hex) function if it exists

I need to format a dictionary with multiple integer lists as hex in python 2.7.

I've found a way to format integers from a dictionary as hex. In this example the hex will work, the hexlist will not.

dict = {   "hex": 0x12,   "hexlist": [0x13, 0x14]}print("{hex:x}, {hexlist:x}".format(**dict))

(Python Sting Formatting - Real Python)

And there is also a way to print a integer list as hex using:

''.join('{:02X}'.format(hex) for hex in hexlist)

(Format ints into string of hex)

But I can't figure out how to combine the two...